Euler 001

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

def sovle(x):
    sum = 0
    for i in range(0, x):
        if (i % 3 == 0 or i % 5 == 0):
            sum += i
    return sum

print solve(1000)